![]() There is just one way to get all four red threes. What is the probability that player got all four red threes?Ī: There are 4 red aces and 100 other cards. Q: Two 52-card decks are shuffled together. Likewise, the probability the player has the third red three is 52/106, and the fourth red three is 51/105. The probability the player has the second red three is 53/107, because the player has 51 cards left, but red three #2 cold be anywhere in the 103 remaining cards. The probability the first red three is in the player's stack is 54/108, since he has half the cards. If you don't dealing with such large numbers, here is an alternative solution. There are combin(104,50)= 1.46691 × 10^28 ways the player could get 48 of the other 100 cards. What is the probability that player got all four red threes?Ī: There are 4 red aces and 104 other cards. ![]() Q: Two 54-card decks (including two jokers) are shuffled together. What are the odds of being dealt all of the Red 3's in a game of Canasta, assuming that all of the cards are dealt?Īllow me to attempt to rephrase the question, hopefully correctly.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |